Learn how to use the Excel MIRR function with syntax and examples.
The Microsoft Excel MIRR function returns the modified internal rate of return for a series of cash flows. The internal rate of return is calculated by using both the cost of the investment and the interest received by reinvesting the cash.
The cash flows must occur at regular intervals, but do not have to be the same amounts for each interval.
The syntax for the Microsoft Excel MIRR function is:
MIRR( range, finance_rate, reinvestment_rate )
range is a range of cells that represent the series of cash flows.
finance_rate is the interest rate that you pay on the cash flow amounts.
reinvestment_rate is the interest rate that you receive on the cash flow amounts as they are reinvested.
The MIRR function can be used in the following versions of Microsoft Excel:
The MIRR function can be used in Microsoft Excel as the following type of function:
Let's look at some Excel MIRR function examples and explore how to use the MIRR function as a worksheet function in Microsoft Excel:
Based on the Excel spreadsheet above:
This first example returns a modified internal rate of return of 19%. It assumes that you start a business at a cost of $7,500 - this amount was borrowed at a rate of 5%. You net the following income for the first four years: $3,000, $5,000, $1,200, and $4,000. The net income was reinvested at a rate of 8%.
=MIRR(A1:A5, 5%, 8%)
This next example returns a modified internal rate of return of 7%. It assumes that you start a business at a cost of $10,000 - this amount was borrowed at a rate of 6.5%. You net the following income for the first three years: $3,400, $6,500, and $1,000. The net income was reinvested at a rate of 10%.
=MIRR(B1:B4, 6.5%, 10%)
The MIRR function can also be used in VBA code in Microsoft Excel. For example:
Dim LNumber As Double Static Values(5) As Double Values(0) = -7500 Values(1) = 3000 Values(2) = 5000 Values(3) = 1200 Values(4) = 4000 LNumber = Mirr(Values(), 0.05, 0.08)
In this example, the variable called LNumber would now contain the value of 0.16506818.
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