MS Excel: DATEDIFF Function (VBA)
In Microsoft Excel, the DATEDIFF function returns the difference between two date values, based on the interval specified.
Syntax
The syntax for the DATEDIFF function is:
DateDiff( interval, date1, date2, [firstdayofweek], [firstweekofyear] )
interval is the interval of time to use to calculate the difference between date1 and date2. Below is a list of valid interval values.
| Interval | Explanation |
|---|---|
| yyyy | Year |
| q | Quarter |
| m | Month |
| y | Day of year |
| d | Day |
| w | Weekday |
| ww | Week |
| h | Hour |
| n | Minute |
| s | Second |
date1 and date2 are the two dates to calculate the difference between.
firstdayofweek is optional. It is a constant that specifies the first day of the week. If this parameter is omitted, Excel assumes that Sunday is the first day of the week.
firstweekofyear is optional. It is a constant that specifies the first week of the year. If this parameter is omitted, Excel assumes that the week containing Jan 1st is the first week of the year.
Applies To
- Excel 2013, Excel 2011 for Mac, Excel 2010, Excel 2007, Excel 2003, Excel XP, Excel 2000
Type of Function
- VBA function (VBA)
VBA Function Example
The DATEDIFF function can only be used in VBA code. Here are some examples of what the DATEDIFF function would return:
| DateDiff("yyyy", "22/11/2003", "22/11/2013") | would return 10 |
| DateDiff("q", "22/11/2003", "22/11/2013") | would return 40 |
| DateDiff("m", "22/11/2011", "1/1/2012") | would return 2 |
For example, you could use the DATEDIFF function in VBA code and create the following function:
Function TestDates (pDate1 as Date, pDate2 as Date) as Long
TestDates = DateDiff("d", pDate1, pDate2)
End Function
Based on the spreadsheet above, the function would return the following values:
| =TestDates(A2, A1) | would return 1 |
| =TestDates(A2, A3) | would return 349 |
| =TestDates(A4, A3) | would return 14 |